Pearson Edexcel International GCSE in Chemistry · 4CH1 · Free · no account needed

Tests for Ions — exam questions

12 original Incandio exam-style questions on Tests for Ions, 26 marks, about 26 minutes of writing. Each one carries the command word, the tariff and the specification statement it assesses, exactly as a paper presents them. This is an original Incandio practice question, written to reflect the structure and demands of the qualification. It is not an official Pearson Edexcel past-paper question.

This is the practice set for Tests for Ions — the lesson that teaches it. Read the lesson first if the idea is new; come here when you want to find out whether you can turn it into marks. Completely free, no account needed to read.

What these questions ask of you

7 command words run through this set, and on Pearson Edexcel International GCSE Chemistry each one means something precise. Answering the wrong command is the commonest way a candidate who understands the lesson still loses the mark.

Which (1 mark)
one option chosen from the set given
Give (1–2 marks)
a short factual answer — the most common chemistry command
Name (1 mark)
the correct chemical name
Describe (2–5 marks)
developed, linked statements of what happens or what is observed Misread as: giving one bare observation where the tariff asked for a developed account
Explain (2–4 marks)
the reason, in terms of particles, bonding, energy or equilibrium Misread as: describing the observation without giving the chemistry that causes it
Suggest (1–3 marks)
a plausible answer applying taught chemistry to an unfamiliar substance
Identify (1–2 marks)
the correct substance or feature selected from what is given

Assessed on Paper 1 (4CH1/1C) and Paper 2 (4CH1/2C), against AO1, AO2, AO3.

Where these sit in the specification

Pearson Edexcel International GCSE Chemistry (4CH1) — statements 2.47 · 2.48. Incandio is aligned to this specification; it is not published by, endorsed by or affiliated with Pearson, and it reproduces none of Pearson's wording.

The 12 questions

Answer them on paper, then open the lesson's exam practice to have them marked. The mark scheme, the accepted and rejected answers and the annotated model answer are in Incandio and are not printed here — an answer beside its question is not practice.

  1. Table 1 — adding sodium hydroxide solution to four solutions
    SolutionWith a little sodium hydroxideOn warming
    Ablue precipitateno further change
    Bgreen precipitateno further change
    Cbrown precipitateno further change
    Dno precipitatepungent gas turns damp red litmus blue

    Tests for negative ions — Halides: add dilute nitric acid, then silver nitrate solution — chloride gives white, bromide cream, iodide yellow. Sulfate: add dilute hydrochloric acid, then barium chloride solution — a white precipitate forms. Carbonate: add dilute acid — fizzing, and the gas turns limewater milky.

    (a)

    (1)Identify

    Identify the ion present in solution C of Table 1.

    Table 1 — adding sodium hydroxide solution to four solutions
    SolutionWith a little sodium hydroxideOn warming
    Ablue precipitateno further change
    Bgreen precipitateno further change
    Cbrown precipitateno further change
    Dno precipitatepungent gas turns damp red litmus blue

    Tests for negative ions — Halides: add dilute nitric acid, then silver nitrate solution — chloride gives white, bromide cream, iodide yellow. Sulfate: add dilute hydrochloric acid, then barium chloride solution — a white precipitate forms. Carbonate: add dilute acid — fizzing, and the gas turns limewater milky.

    Specification 2.47 · AO2 · about 1 min

    (b)

    (2)Give

    Give the ions present in solutions A and B of Table 1.

    Table 1 — adding sodium hydroxide solution to four solutions
    SolutionWith a little sodium hydroxideOn warming
    Ablue precipitateno further change
    Bgreen precipitateno further change
    Cbrown precipitateno further change
    Dno precipitatepungent gas turns damp red litmus blue

    Tests for negative ions — Halides: add dilute nitric acid, then silver nitrate solution — chloride gives white, bromide cream, iodide yellow. Sulfate: add dilute hydrochloric acid, then barium chloride solution — a white precipitate forms. Carbonate: add dilute acid — fizzing, and the gas turns limewater milky.

    Specification 2.47 · AO2 · about 2 min

    (c)

    (3)Explain

    Explain how solution D in Table 1 behaves differently from the other three, and what this shows.

    Table 1 — adding sodium hydroxide solution to four solutions
    SolutionWith a little sodium hydroxideOn warming
    Ablue precipitateno further change
    Bgreen precipitateno further change
    Cbrown precipitateno further change
    Dno precipitatepungent gas turns damp red litmus blue

    Tests for negative ions — Halides: add dilute nitric acid, then silver nitrate solution — chloride gives white, bromide cream, iodide yellow. Sulfate: add dilute hydrochloric acid, then barium chloride solution — a white precipitate forms. Carbonate: add dilute acid — fizzing, and the gas turns limewater milky.

    Specification 2.47 · AO2 · about 3 min

    (d)

    (3)Suggest

    A student tested solution A for a halide but forgot the nitric acid, and reported a positive result. Suggest why her conclusion cannot be trusted.

    Table 1 — adding sodium hydroxide solution to four solutions
    SolutionWith a little sodium hydroxideOn warming
    Ablue precipitateno further change
    Bgreen precipitateno further change
    Cbrown precipitateno further change
    Dno precipitatepungent gas turns damp red litmus blue

    Tests for negative ions — Halides: add dilute nitric acid, then silver nitrate solution — chloride gives white, bromide cream, iodide yellow. Sulfate: add dilute hydrochloric acid, then barium chloride solution — a white precipitate forms. Carbonate: add dilute acid — fizzing, and the gas turns limewater milky.

    Specification 2.48 · AO3 · about 3 min

    (Total for Question 1 = 9 marks)

  2. (1)Which

    Which ion gives a blue precipitate with sodium hydroxide solution?

    Ion
    Airon(II)
    Biron(III)
    Ccopper(II)
    Dammonium

    Specification 2.47 · AO1 · about 1 min

    (Total for Question 2 = 1 mark)

  3. (1)Give

    Give the colour of the precipitate formed when silver nitrate is added to an acidified chloride solution.

    Tests for negative ions — Halides: add dilute nitric acid, then silver nitrate solution — chloride gives white, bromide cream, iodide yellow. Sulfate: add dilute hydrochloric acid, then barium chloride solution — a white precipitate forms. Carbonate: add dilute acid — fizzing, and the gas turns limewater milky.

    Specification 2.48 · AO1 · about 1 min

    (Total for Question 3 = 1 mark)

  4. (1)Name

    Name the reagent added after dilute hydrochloric acid when testing for a sulfate ion.

    Tests for negative ions — Halides: add dilute nitric acid, then silver nitrate solution — chloride gives white, bromide cream, iodide yellow. Sulfate: add dilute hydrochloric acid, then barium chloride solution — a white precipitate forms. Carbonate: add dilute acid — fizzing, and the gas turns limewater milky.

    Specification 2.48 · AO1 · about 1 min

    (Total for Question 4 = 1 mark)

  5. (2)Describe

    Describe the test for an ammonium ion and the result that confirms it.

    Specification 2.47 · AO1 + AO2 · about 2 min

    (Total for Question 5 = 2 marks)

  6. (3)Explain

    Explain why dilute nitric acid is added before the silver nitrate in the test for a halide ion.

    Tests for negative ions — Halides: add dilute nitric acid, then silver nitrate solution — chloride gives white, bromide cream, iodide yellow. Sulfate: add dilute hydrochloric acid, then barium chloride solution — a white precipitate forms. Carbonate: add dilute acid — fizzing, and the gas turns limewater milky.

    Specification 2.48 · AO2 · about 3 min

    (Total for Question 6 = 3 marks)

  7. (2)Explain

    Explain why sodium hydroxide solution produces a precipitate with copper(II) ions but not with sodium ions.

    Specification 2.47 · AO2 · about 2 min

    (Total for Question 7 = 2 marks)

  8. (3)Suggest

    Suggest a sequence of tests that would identify a solution as iron(III) sulfate, and say what each test would show.

    Tests for negative ions — Halides: add dilute nitric acid, then silver nitrate solution — chloride gives white, bromide cream, iodide yellow. Sulfate: add dilute hydrochloric acid, then barium chloride solution — a white precipitate forms. Carbonate: add dilute acid — fizzing, and the gas turns limewater milky.

    Specification 2.47, 2.48 · AO2 + AO3 · about 3 min

    (Total for Question 8 = 3 marks)

  9. (4)Explain

    Explain why dilute nitric acid is added before barium chloride when testing for sulfate ions, and why hydrochloric acid must not be used instead.

    Specification 2.47, 2.48 · AO1 + AO2 · about 4 min

    (Total for Question 9 = 4 marks)

Have them marked, then defend the answer

Practice tells you the mark; teaching it back tells you whether you understand it. On Incandio a topic counts as mastered only once you have taught it and defended it.

  1. Mark these questions — 12 questions, marked on Incandio against the authored scheme, with the mistake you actually made named.
  2. Teach it — explain Tests for Ions to Ember, an AI pupil who does not have it yet and asks the awkward question.
  3. Defend it — argue it against Carl Remigius Fresenius over three rounds, marked against descriptors you can read first.

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